Reply to post: Re: when does 92^n > 62^(n+1) ?

Third of US banks OK with passwords even social networks reject

Paul Kinsler

Re: when does 92^n > 62^(n+1) ?

n log(92) > (n+1) log(62)

n (log(92)-log(62)) > log(62)

n > log(62) / (log(92)-log(62))

n >= 11 (for integer n)

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