#### and now for some math...

(If something is wrong with this, please correct me)

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Given:

127.03 AU approximate distance traveled so far by Voyager 1

4.2421 ly is the approximate distance to nearest star from Earth

Find:

How long would it take at Voyager 1's average speed so far, to go the distance of Earth to Earth's nearest star?

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My Answer:

Approximately 76568 years. Last digits maybe off due to rounding, etc...?

Although, I got 76576 years from Qalculate with units, and 76566 years from Ti Voyage 200 with units.

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// Research:

127.03 AU is approximately 0.7336640935983627 light days

127.03 AU is approximately 0.002008662816152567 light years

From September 5, 1977 to December 7, 2013 is 13,242 days

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// Using Qalculate without units:

(4.2421ly)*(13242d)/(.73366ld*(ly/(365.25ld)))=___

(4.2421 ⋅ 13242) ∕ (0.73366 ∕ 365.25)

≈ 27965968.79351470709

days

((4.2421 ⋅ 13242) ∕ (0.73366 ∕ 365.25)) ∕ 365.2425

≈ 76568.22191698586

years

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// Using Qalculate with units:

4.2421⋅ly⋅13242⋅day/(127.03⋅AU) = (4.2421 ⋅ lightyear ⋅ 13242 ⋅ day) ∕ (127.03 ⋅ astronomical_unit)

≈ 2.4165557924 Ts

≈ 76.57603215692 kiloyears

// Qalculate Uses

ly = lightyear ≈ 9.46073047258 Pm

day = day = 86.4 ks

AU = astronomical_unit = 149.5787066 Gm

year = year = 31.5576 Ms

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// Using Ti Voyage 200 with units:

4.2421*_ltyr*13242*_day/(127.03*_au)

≈ 2.41619E12*_s

≈ 2416194140896.8*_s

≈ 76566.207457403*_yr

// Ti Voyage 200 uses

1*_ltyr = 9.4605284048794E15*_m

1*_day = 86400.*_s

1*_au = 149597900000.*_m

1*_yr = 365.24219878125*_day

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// Web Sources:

http://en.wikipedia.org/wiki/Voyager_1

http://en.wikipedia.org/wiki/List_of_nearest_stars

http://en.wikipedia.org/wiki/Light_year

http://en.wikipedia.org/wiki/Julian_year_%28astronomy%29

http://en.wikipedia.org/wiki/Year

http://www.convertunits.com/from/AU/to/light+day

http://www.convertunits.com/from/AU/to/light+year

http://www.timeanddate.com/date/durationresult.html?m1=9&d1=5&y1=1977&m2=12&d2=7&y2=2013

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// Calculator Sources:

Voyage 200, Qalculate

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p.s. for those who want more digits in light days for my calculation...

((4.2421 ⋅ 13242) ∕ (0.7336640935983627 ∕ 365.25)) ∕ 365.2425

≈ 76567.79469211468